Where is iar program start

So, the vector table is starting from 0x That vector table will contain all the locations of the exception and interrupt ISR.

As Cortex-M4 has below exceptions, interrupts and those things are ordered in the below image. So, 0x address contains initial Stack Pointer Value. Then 0x has the address of the reset handler. Once you press the reset button or power up the controller, below things will happen. Note: These above 3 steps are done by the hardware This is architecture-specific. This is how your main is getting called while power-up or press the reset button.

You may understand clearly if you see the execution below. I am going to run through a debugger J-Link. Using that we will step by step. The above code is not a full code. I just provided some lines for your understanding. It is possible to override it. But if the PC is loaded with the second entry of the vector table on reset, what is the IAR entry point used for?

How are we doing? Please help us improve Stack Overflow. Take our short survey. Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Collectives on Stack Overflow. Learn more. Ask Question. Asked 6 years, 10 months ago. J-link is my debugger interface. When debugger is connected, the software runs even without startup file. But I want to run without debugger, hence cstartup. Now the issue is, if I include the "cstartup.

The code snippet of my startup. Viewed 4k times. What is this and where is located?? Improve this question. KansaiRobot KansaiRobot 4, 4 4 gold badges 35 35 silver badges 76 76 bronze badges. It's the program entry point, usually in cstartup. I suggest that you read the IAR manual s both for ide and the compiler. Add a comment. Active Oldest Votes. Improve this answer. Eyal B Eyal B 21 2 2 bronze badges.